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Bandwidth & bit rate (example)
Data is transmitted using a transmission scheme with eight levels per signal element (M). If the channel has a bandwidth (B) of 3100 Hz, what is the theoretical maximum bit rate (C)?
C = 2B log2 M (Nyquist formula)
Therefore
C = 2 x 3100 log2 8 = 18 600 bps
The log2 M part of the formula gives the number of bits coded by one signal level.
For a bandwidth B the maximum bit rate is 2B.
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